Hi,

syzkaller found that pf is logging debug information while holding
a mutex.  That is not allowed.

pf fragment mutex -> log(9) -> kernel lock

https://syzkaller.appspot.com/bug?extid=de885339faa7e0a8cb83

Easiest fix is to convert pf fragment mutex to rwlock.

ok?

bluhm

Index: net/pf_norm.c
===================================================================
RCS file: /data/mirror/openbsd/cvs/src/sys/net/pf_norm.c,v
diff -u -p -r1.238 pf_norm.c
--- net/pf_norm.c	28 May 2026 06:41:24 -0000	1.238
+++ net/pf_norm.c	27 Jun 2026 18:59:26 -0000
@@ -143,9 +143,9 @@ int			 pf_reassemble6(struct mbuf **, st
 struct pool		 pf_frent_pl, pf_frag_pl, pf_frnode_pl;
 struct pool		 pf_state_scrub_pl;
 
-struct mutex		 pf_frag_mtx;
+struct rwlock		 pf_frag_lock;
 
-#define PF_FRAG_LOCK_INIT()	mtx_init(&pf_frag_mtx, IPL_SOFTNET)
+#define PF_FRAG_LOCK_INIT()	rw_init(&pf_frag_lock, "pffrag")
 
 void
 pf_normalize_init(void)
Index: net/pfvar_priv.h
===================================================================
RCS file: /data/mirror/openbsd/cvs/src/sys/net/pfvar_priv.h,v
diff -u -p -r1.42 pfvar_priv.h
--- net/pfvar_priv.h	5 Feb 2026 03:26:00 -0000	1.42
+++ net/pfvar_priv.h	27 Jun 2026 18:58:50 -0000
@@ -622,7 +622,7 @@ void			 pf_state_unref(struct pf_state *
 
 extern struct rwlock	pf_lock;
 extern struct rwlock	pf_state_lock;
-extern struct mutex	pf_frag_mtx;
+extern struct rwlock	pf_frag_lock;
 extern struct mutex	pf_inp_mtx;
 
 #define PF_LOCK()		do {			\
@@ -668,8 +668,8 @@ extern struct mutex	pf_inp_mtx;
 			    rw_status(&pf_state_lock), __func__);\
 	} while (0)
 
-#define PF_FRAG_LOCK()		mtx_enter(&pf_frag_mtx)
-#define PF_FRAG_UNLOCK()	mtx_leave(&pf_frag_mtx)
+#define PF_FRAG_LOCK()		rw_enter_write(&pf_frag_lock)
+#define PF_FRAG_UNLOCK()	rw_exit_write(&pf_frag_lock)
 
 /* for copies to/from network byte order */
 void			pf_state_peer_hton(const struct pf_state_peer *,