From: Alexandre Ratchov Subject: Re: aucat: Add generic channel mapping in place of -j and -c options. To: Jan Stary Cc: tech@openbsd.org Date: Mon, 18 Mar 2024 15:36:51 +0100 On Mon, Mar 18, 2024 at 01:30:51PM +0100, Jan Stary wrote: > I find the swapped order of A/B in -m A/B for -o files > a bit confusing; for example, the manpage example > > aucat -n -i stereo.wav -c 1 > -m 0:0/0:0 -o left.wav > -m 0:0/1:1 -o right.wav > > creates the right.wav having the (only) 0:0 channel > take its data *from* the 1:1 channel of -i stereo.wav; > > It is one of the two possibilities of course, > but having the meaning of -m A/B uniform of both -i and -o files > would be slightly less confusing imho. > Well, it's uniform: file channels first, followed by device channels. But I get your point: my eyes are also used to see the producer followed by the consumer. Indeed, producer and consumer get swapped: the file is the producer in the playback case, and consumer in the recording case). > > +.It Fl m Ar min : Ns Ar max Ns / Ns Ar min : Ns Ar max > > +Map the given range of file channels into the given range of > > +device channels. > > If it stays swapped as in the current diff, > the manpage should perhaps say so explicitly. > The man page is correct (file first, device second). But they look swapped if you think in terms of producer vs consumer. > Also, with -n, there is no "device", so no "device channels". > Would it be clearer to talk about "input channels" and "output channels" > instead in the Fl m portion of the manpage? > Yeah, we should explain what -n does: FWIW, it creates an internal pseudo-device that records what it plays. So the concept of device channels remains. Or should we say "bus" instead of device? But that's for another diff