From: Jonas Bechtel Subject: [PATCH] awk: proposal: reduce utf8 scanning To: millert@openbsd.org Cc: tech@openbsd.org Date: Sun, 2 Jun 2024 10:06:11 +0200 Hi, (CC to tech@openbsd.org, don't know whether it comes through) I found recent progress for utf8 support in awk which I am using from now on. However, I suggest reducing string scanning as follows: --- run.c.orig Sun May 5 00:59:21 2024 +++ run.c.new Sun Jun 2 09:21:14 2024 @@ -606,16 +606,14 @@ int u8_isutf(const char *s) unsigned char c; c = s[0]; - if (c < 128 || awk_mb_cur_max == 1) - return 1; /* what if it's 0? */ - - n = strlen(s); - if (n >= 2 && ((c>>5) & 0x7) == 0x6 && (s[1] & 0xC0) == 0x80) { + if (c < 128 || awk_mb_cur_max == 1) { + ret = 1; /* what if it's 0? */ + } else if (((c>>5) & 0x7) == 0x6 && (s[1] & 0xC0) == 0x80) { ret = 2; /* 110xxxxx 10xxxxxx */ - } else if (n >= 3 && ((c>>4) & 0xF) == 0xE && (s[1] & 0xC0) == 0x80 + } else if (((c>>4) & 0xF) == 0xE && (s[1] & 0xC0) == 0x80 && (s[2] & 0xC0) == 0x80) { ret = 3; /* 1110xxxx 10xxxxxx 10xxxxxx */ - } else if (n >= 4 && ((c>>3) & 0x1F) == 0x1E && (s[1] & 0xC0) == 0x80 + } else if (((c>>3) & 0x1F) == 0x1E && (s[1] & 0xC0) == 0x80 && (s[2] & 0xC0) == 0x80 && (s[3] & 0xC0) == 0x80) { ret = 4; /* 11110xxx 10xxxxxx 10xxxxxx 10xxxxxx */ } else { @@ -1018,7 +1016,7 @@ Cell *substr(Node **a, int nnn) /* substr(a[0], a[1], DPRINTF("substr: m=%d, n=%d, s=%s\n", m, n, s); y = gettemp(); mb = u8_char2byte(s, m-1); /* byte offset of start char in s */ - nb = u8_char2byte(s, m-1+n); /* byte offset of end+1 char in s */ + nb = mb+u8_char2byte(&s[mb], n); /* byte offset of end+1 char in s */ temp = s[nb]; /* with thanks to John Linderman */ s[nb] = '\0'; a) strlen is not needed because the check for 0b110xxxxx/0b1110xxxx/0b11110xxx and 0b10xxxxxx ensure that no 0 is read. strlen would read the entire string for every single codepoint b) starting position for second scan adjusted Best Regards jbechtel